Comments on: Pulling Drop-down values from a database using Javascript and PHP

By: Edy

Edy — Thu, 13 Nov 2008 01:33:43 +0000

it can handle only max 60 data table

By: frame

frame — Thu, 23 Oct 2008 13:26:00 +0000

Great script…

Just wondering, is it possible to insert the chosen option into SQL.

Eg, the person choose, male as grp option, which open up boots and pants.

In the person table, there is a id, grp_id and category _id…so it is possible to get the grp_id and category_id from javascript and post it into MYSQL.

Thanks!

By: Rudy Greene

Rudy Greene — Tue, 14 Oct 2008 14:43:12 +0000

Regarding my earlier comment. The script works great. I had filled the first table with my own categories so they didn’t match with the rest of the script. My bad.

By: Rudy Greene

Rudy Greene — Tue, 14 Oct 2008 14:11:17 +0000

This is a terrific idea for a script, but it doesn’t actually work. The first box will populate fine, but there is something wrong with the Javascript on the other two.

By: Ben

Ben — Sun, 28 Sep 2008 06:22:11 +0000

I am new to php and mysql and this has been very helpful in my learning, however i have not been able to get it working. My page ends up with the 3 drop down menus, but it just says main, category and sub category. I am not getting the data from the server. I have copied your tutorial exactly, except one set of modifications which was my db connection string. I am not sure if this is an error on your site, but when i went to test the connection.php file i got an error. I had to put an ‘ after servername_dbname and database name to get it to work. The code below was just copied from your site and is missing the ‘.

$servername=’localhost’;
$dbusername=’servername_dbname;
$dbpassword=’password’;
$dbname=’database name;

When i go to the update.php page, i get function fillCategory(){ and all the data from the server, but i cant get the program to function.

Thanks,
Ben

By: Zac

Zac — Thu, 25 Sep 2008 02:33:28 +0000

Mike, thanks for taking the time to publish your code. Any update on a running example?

Cheers

By: Ogunyankin Omotayo Rapheal

Ogunyankin Omotayo Rapheal — Fri, 19 Sep 2008 09:24:45 +0000

this is a great job,you are quiet appreciated,please ive been finding it difficult to validate my work on HTML using javascript i will be so happy if you can just send me the most important steps to follow or codes in using javascript validate a form,also using javascript to create a function like solving some Mathematical problems, thanks Tayo

By: geocine

geocine — Fri, 12 Sep 2008 18:20:47 +0000

oopps copied it straight from my edited code here it is..

echo “i = document.drop_list.Category.value;”;
echo “if( !(i > \”{$nt4['category']}\” && i < \”{$nt4['category']}\”) ){”;

By: geocine

geocine — Fri, 12 Sep 2008 18:19:29 +0000

and this one to work out strings with apostrophe’s

echo “i = document.addRecord.events.value;”;
echo “if( !(i > \”{$nt4['category']}\” && i < \”{$nt4['category']}\”) ){”;

By: geocine

geocine — Fri, 12 Sep 2008 17:55:47 +0000

this is just my opinion..

change this

if(document.drop_list.Category.value == ‘$nt4[category]‘)

to this

echo “if(document.drop_list.Category.value == \”{$nt4[category]}\”)

since it might turn out like this

if(document.drop_list.Category.value == ‘Geocine’s’)

that will generate javascript error..